fast-bwa/bseq.c

56 lines
1.5 KiB
C

#include <zlib.h>
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include "bseq.h"
#include "kseq.h"
KSEQ_INIT2(, gzFile, gzread)
static inline void trim_readno(kstring_t *s)
{
if (s->l > 2 && s->s[s->l-2] == '/' && isdigit(s->s[s->l-1]))
s->l -= 2, s->s[s->l] = 0;
}
static inline void kseq2bseq1(const kseq_t *ks, bseq1_t *s)
{ // TODO: it would be better to allocate one chunk of memory, but probably it does not matter in practice
s->name = strdup(ks->name.s);
s->comment = ks->comment.l? strdup(s->comment) : 0;
s->seq = strdup(ks->seq.s);
s->qual = ks->qual.l? strdup(ks->qual.s) : 0;
s->l_seq = strlen(s->seq);
}
bseq1_t *bseq_read(int chunk_size, int *n_, void *ks1_, void *ks2_)
{
kseq_t *ks = (kseq_t*)ks1_, *ks2 = (kseq_t*)ks2_;
int size = 0, m, n;
bseq1_t *seqs;
m = n = 0; seqs = 0;
while (kseq_read(ks) >= 0) {
if (ks2 && kseq_read(ks2) < 0) { // the 2nd file has fewer reads
fprintf(stderr, "[W::%s] the 2nd file has fewer sequences.\n", __func__);
break;
}
if (n >= m) {
m = m? m<<1 : 256;
seqs = realloc(seqs, m * sizeof(bseq1_t));
}
trim_readno(&ks->name);
kseq2bseq1(ks, &seqs[n]);
size += seqs[n++].l_seq;
if (ks2) {
trim_readno(&ks2->name);
kseq2bseq1(ks2, &seqs[n]);
size += seqs[n++].l_seq;
}
if (size >= chunk_size) break;
}
if (size == 0) { // test if the 2nd file is finished
if (ks2 && kseq_read(ks2) >= 0)
fprintf(stderr, "[W::%s] the 1st file has fewer sequences.\n", __func__);
}
*n_ = n;
return seqs;
}