bwa_perf/bwt.cpp

393 lines
14 KiB
C++
Raw Normal View History

#include <stdint.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <string>
#include <iostream>
#include "util.h"
#include "bwt.h"
using namespace std;
const static char BASE[4] = {'A', 'C', 'G', 'T'};
// 打印32位整型数据中包含的pre-bwtbwt
static void print_base_uint32(uint32_t p)
{
const char BASE[4] = {'A', 'C', 'G', 'T'};
for (int i = 30; i > 0; i -= 2)
{
int b1 = p >> i & 3;
cout << BASE[b1] << endl;
}
}
void dump_bwt(const char *fn, const bwt_t *bwt)
{
FILE *fp;
fp = xopen(fn, "wb");
err_fwrite(&bwt->primary, sizeof(bwtint_t), 1, fp);
err_fwrite(bwt->L2 + 1, sizeof(bwtint_t), 4, fp);
err_fwrite(bwt->bwt, 4, bwt->bwt_size, fp);
err_fflush(fp);
err_fclose(fp);
}
// 计算一个字节构成的T,G,C,A序列对应的每个碱基的个数(按T,G,C,A顺序存储在32位整数中每个占8位)
void bwt_gen_cnt_table(bwt_t *bwt)
{
int i, j;
for (i = 0; i != 256; ++i)
{
uint32_t x = 0;
for (j = 0; j != 4; ++j)
x |= (((i & 3) == j) + ((i >> 2 & 3) == j) + ((i >> 4 & 3) == j) + (i >> 6 == j)) << (j << 3);
bwt->cnt_table[i] = x;
}
}
// 解析两bit的bwt碱基序列这个只有bwt str可以包含也可不包含occ check point
bwt_t *restore_bwt(const char *fn)
{
bwt_t *bwt;
bwt = (bwt_t *)calloc(1, sizeof(bwt_t));
FILE *fp = fopen(fn, "rb");
fseek(fp, 0, SEEK_END);
bwt->bwt_size = (ftell(fp) - sizeof(bwtint_t) * 5) >> 2; // 以32位word为单位计算的size
bwt->bwt = (uint32_t *)calloc(bwt->bwt_size, 4);
fseek(fp, 0, SEEK_SET);
fread(&bwt->primary, sizeof(bwtint_t), 1, fp);
fread(bwt->L2 + 1, sizeof(bwtint_t), 4, fp);
fread_fix(fp, bwt->bwt_size << 2, bwt->bwt);
bwt->seq_len = bwt->L2[4];
// char *buf = (char *)calloc(bwt->seq_len + 1, 1);
// for (bwtint_t i = 0; i < bwt->seq_len; ++i)
// {
// buf[i] = BASE[bwt->bwt[i >> 4] >> ((15 - (i & 15)) << 1) & 3];
// cout << buf[i];
// }
// cout << endl;
fclose(fp);
bwt_gen_cnt_table(bwt); // 字节所能表示的各种碱基组合中,各个碱基的累积数量
return bwt;
}
// 根据原始的字符串bwt创建interval-bwt用uint32_t来表示occ
void create_interval_occ_bwt(bwt_t *bwt)
{
bwtint_t i, k, n_occ;
uint32_t *buf;
uint32_t c[4];
n_occ = (bwt->seq_len + OCC_INTERVAL - 1) / OCC_INTERVAL + 1;
bwt->bwt_size += n_occ * 4; // the new size
buf = (uint32_t *)calloc(bwt->bwt_size, 4); // will be the new bwt
c[0] = c[1] = c[2] = c[3] = 0;
// 计算occ生成naive bwt
for (i = k = 0; i < bwt->seq_len; ++i)
{
if (i % 1000000 == 0)
{
cout << "line: " << i << '\t' << ((uint64_t)c[0] + c[1] + c[2] + c[3]) << '\t';
cout << c[0] << ' ' << c[1] << ' ' << c[2] << ' ' << c[3] << endl;
}
if (i % OCC_INTERVAL == 0)
{
memcpy(buf + k, c, sizeof(uint32_t) * 4);
k += 4; // in fact: sizeof(bwtint_t)=4*(sizeof(bwtint_t)/4) 每个c包含多少个32位
}
if (i % 16 == 0)
buf[k++] = bwt->bwt[i / 16]; // 16 == sizeof(uint32_t)/2, 2个bit表示一个碱基
++c[bwt_B00(bwt, i)];
}
// the last element
// cout << c[0] << '\t' << c[1] << '\t' << c[2] << '\t' << c[3] << endl;
memcpy(buf + k, c, sizeof(uint32_t) * 4);
xassert(k + 4 == bwt->bwt_size, "inconsistent bwt_size");
// update bwt
free(bwt->bwt);
bwt->bwt = buf;
}
// 对64位整型数据y计算碱基c的累积个数
static inline int __occ_aux(uint64_t y, int c)
{
// reduce nucleotide counting to bits counting
y = ((c & 2) ? y : ~y) >> 1 & ((c & 1) ? y : ~y) & 0x5555555555555555ull;
// count the number of 1s in y
y = (y & 0x3333333333333333ull) + (y >> 2 & 0x3333333333333333ull);
return ((y + (y >> 4)) & 0xf0f0f0f0f0f0f0full) * 0x101010101010101ull >> 56;
}
// k行(包含)之前碱基c的累计总数, interval大于等于32才能正确计算
bwtint_t bwt_occ(const bwt_t *bwt, bwtint_t k, uint8_t c)
{
bwtint_t n;
uint32_t *p, *end;
if (k == bwt->seq_len)
return bwt->L2[c + 1] - bwt->L2[c];
if (k == (bwtint_t)(-1))
return 0;
k -= (k >= bwt->primary); // because $ is not in bwt
// retrieve Occ at k/OCC_INTERVAL
n = ((bwtint_t *)(p = bwt_occ_intv(bwt, k)))[c];
// cout << "bwt_occ - 1: " << (int)c << '\t' << k << '\t' << n << endl;
p += sizeof(bwtint_t); // jump to the start of the first BWT cell
// calculate Occ up to the last k/32
end = p + (((k >> 5) - ((k & ~OCC_INTV_MASK) >> 5)) << 1);
for (; p < end; p += 2)
n += __occ_aux((uint64_t)p[0] << 32 | p[1], c);
// cout << "bwt_occ - 2: " << (int)c << '\t' << k << '\t' << n << endl;
// calculate Occ
n += __occ_aux(((uint64_t)p[0] << 32 | p[1]) & ~((1ull << ((~k & 31) << 1)) - 1), c);
if (c == 0)
n -= ~k & 31; // corrected for the masked bits
// cout << "bwt_occ - 3: " << (int)c << '\t' << k << '\t' << n << endl;
return n;
}
// 统计k行bwt mtx行之前4种碱基累积数量这里的k是bwt矩阵里的行比bwt字符串多1
void bwt_occ4(const bwt_t *bwt, bwtint_t k, bwtint_t cnt[4])
{
bwtint_t x = 0;
uint32_t *p, tmp, *end;
// bwtint_t bwt_k_base_line = k >> OCC_INTV_SHIFT << OCC_INTV_SHIFT;
if (k == (bwtint_t)(-1))
{
memset(cnt, 0, 4 * sizeof(bwtint_t));
return;
}
k -= (k >= bwt->primary); // because $ is not in bwt
p = bwt_occ_intv(bwt, k);
//cout << "k: " << k << "; occ: " << p[0] << ' ' << p[1] << ' ' << p[2] << ' ' << p[3] << endl;
cnt[0] = p[0];
cnt[1] = p[1];
cnt[2] = p[2];
cnt[3] = p[3];
p += 4; // sizeof(bwtint_t) = 4*(sizeof(bwtint_t)/sizeof(uint32_t))
end = p + ((k >> 4) - ((k & ~OCC_INTV_MASK) >> 4)); // this is the end point of the following loop
//end = p + 1;
// cout << "k - kbase: " << k - bwt_k_base_line << endl;
for (; p < end; ++p)
{
x += __occ_aux4(bwt, *p);
//if (k == 3965453116 || k == 3965453672 || k == 2668688087 || k == 2668688550)
// print_base_uint32(*p);
}
tmp = *p & ~((1U << ((~k & 15) << 1)) - 1);
//if (k == 3965453116 || k == 3965453672 || k == 2668688087 || k == 2668688550)
// print_base_uint32(tmp);
x += __occ_aux4(bwt, tmp) - (~k & 15); // 这里多算了A要减去
cnt[0] += x & 0xff;
cnt[1] += x >> 8 & 0xff;
cnt[2] += x >> 16 & 0xff;
cnt[3] += x >> 24;
//if (k == 3965453116 || k == 3965453672 || k == 2668688087 || k == 2668688550)
// cout << "final-occ: " << cnt[0] << ' ' << cnt[1] << ' ' << cnt[2] << ' ' << cnt[3] << endl;
}
// an analogy to bwt_occ4() but more efficient, requiring k <= l
void bwt_2occ4(const bwt_t *bwt, bwtint_t k, bwtint_t l, bwtint_t cntk[4], bwtint_t cntl[4])
{
// double tm_t = realtime();
// bwt_occ4(bwt, k, cntk);
// bwt_occ4(bwt, l, cntl);
// return;
bwtint_t _k, _l;
_k = k - (k >= bwt->primary);
_l = l - (l >= bwt->primary);
if (_l >> OCC_INTV_SHIFT != _k >> OCC_INTV_SHIFT || k == (bwtint_t)(-1) || l == (bwtint_t)(-1))
{
bwt_occ4(bwt, k, cntk);
bwt_occ4(bwt, l, cntl);
}
else
{
bwtint_t x, y;
uint32_t *p, tmp, *endk, *endl;
k -= (k >= bwt->primary); // because $ is not in bwt
l -= (l >= bwt->primary);
p = bwt_occ_intv(bwt, k);
cntk[0] = p[0];
cntk[1] = p[1];
cntk[2] = p[2];
cntk[3] = p[3];
p += 4; // sizeof(bwtint_t) = 4*(sizeof(bwtint_t)/sizeof(uint32_t))
// prepare cntk[]
endk = p + ((k >> 4) - ((k & ~OCC_INTV_MASK) >> 4));
endl = p + ((l >> 4) - ((l & ~OCC_INTV_MASK) >> 4));
for (x = 0; p < endk; ++p)
x += __occ_aux4(bwt, *p);
y = x;
tmp = *p & ~((1U << ((~k & 15) << 1)) - 1);
x += __occ_aux4(bwt, tmp) - (~k & 15);
// calculate cntl[] and finalize cntk[]
for (; p < endl; ++p)
y += __occ_aux4(bwt, *p);
tmp = *p & ~((1U << ((~l & 15) << 1)) - 1);
y += __occ_aux4(bwt, tmp) - (~l & 15);
memcpy(cntl, cntk, 4 * sizeof(bwtint_t));
cntk[0] += x & 0xff;
cntk[1] += x >> 8 & 0xff;
cntk[2] += x >> 16 & 0xff;
cntk[3] += x >> 24;
cntl[0] += y & 0xff;
cntl[1] += y >> 8 & 0xff;
cntl[2] += y >> 16 & 0xff;
cntl[3] += y >> 24;
}
// t5 += realtime() - tm_t;
// f1 += 1;
}
void bwt_extend(const bwt_t *bwt, const bwtintv_t *ik, bwtintv_t ok[4], int is_back)
{
bwtint_t tk[4], tl[4];
int i;
bwt_2occ4(bwt, ik->x[!is_back] - 1, ik->x[!is_back] - 1 + ik->x[2], tk, tl); // tk表示在k行之前所有各个碱基累积出现次数tl表示在l行之前的累积
// cout << "bwt-1-d: " << ik->x[!is_back] - 1 << '\t' << tk[0] << '\t' << tk[1] << '\t' << tk[2] << '\t' << tk[3] << endl;
// cout << "bwt-1-d: " << ik->x[!is_back] - 1 + ik->x[2] << '\t' << tl[0] << '\t' << tl[1] << '\t' << tl[2] << '\t' << tl[3] << endl;
// 这里是反向扩展
for (i = 0; i != 4; ++i)
{
ok[i].x[!is_back] = bwt->L2[i] + 1 + tk[i]; // 起始行位置,互补链
ok[i].x[2] = tl[i] - tk[i]; // 间隔
}
// 因为计算的是互补碱基所以3对应着0,2对应1下边是正向扩展
ok[3].x[is_back] = ik->x[is_back] + (ik->x[!is_back] <= bwt->primary && ik->x[!is_back] + ik->x[2] - 1 >= bwt->primary);
ok[2].x[is_back] = ok[3].x[is_back] + ok[3].x[2];
ok[1].x[is_back] = ok[2].x[is_back] + ok[2].x[2];
ok[0].x[is_back] = ok[1].x[is_back] + ok[1].x[2];
}
// 利用bwt搜索seed完整搜索只需要单向搜索
void bwt_search(bwt_t *bwt, const string &q)
{
bwtintv_t ik, ok[4];
int i, c, x = 0;
bwt_set_intv(bwt, bval(q[x]), ik);
ik.info = x + 1;
// cout << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
for (i = x + 1; i < (int)q.size(); ++i)
{
if (bval(q[i]) < 4)
{
c = cbval(q[i]);
bwt_extend(bwt, &ik, ok, 0);
ik = ok[c];
ik.info = i + 1;
// cout << "bwt-1: " << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
}
}
}
// 扩展两次
void bwt_extend2(const bwt_t *bwt, bwtintv_t *ik, bwtintv_t ok[4], int is_back, int c1, int c2)
{
bwtint_t tk[4], tl[4];
// oc1, oc2;
// int int1 = 0, int2 = 0;
int i;
bwt_2occ4(bwt, ik->x[!is_back] - 1, ik->x[!is_back] - 1 + ik->x[2], tk, tl); // tk表示在k行之前所有各个碱基累积出现次数tl表示在l行之前的累积
// 这里是反向扩展
for (i = 0; i != 4; ++i)
{
ok[i].x[!is_back] = bwt->L2[i] + 1 + tk[i]; // 起始行位置,互补链
ok[i].x[2] = tl[i] - tk[i]; // 间隔
}
// 因为计算的是互补碱基所以3对应着0,2对应1下边是正向扩展
ok[3].x[is_back] = ik->x[is_back] + (ik->x[!is_back] <= bwt->primary && ik->x[!is_back] + ik->x[2] - 1 >= bwt->primary);
ok[2].x[is_back] = ok[3].x[is_back] + ok[3].x[2];
ok[1].x[is_back] = ok[2].x[is_back] + ok[2].x[2];
ok[0].x[is_back] = ok[1].x[is_back] + ok[1].x[2];
//cout << (ik->x[!is_back] <= bwt->primary && ik->x[!is_back] + ik->x[2] - 1 >= bwt->primary) << endl;
*ik = ok[c1];
//oc1 = oc2 = 0;
//for (i = 3; i > c1; --i)
//{
// int1 += tl[i] - tk[i];
// oc1 += tk[i];
// oc2 += tl[i];
//}
//cout << "bwt-2 interval-1: " << int1 << ' ' << oc1 << ' ' << oc2 << endl;
bwt_2occ4(bwt, ik->x[!is_back] - 1, ik->x[!is_back] - 1 + ik->x[2], tk, tl);
for (i = 0; i != 4; ++i)
{
ok[i].x[!is_back] = bwt->L2[i] + 1 + tk[i]; // 起始行位置,互补链
ok[i].x[2] = tl[i] - tk[i]; // 间隔
}
// 因为计算的是互补碱基所以3对应着0,2对应1下边是正向扩展
ok[3].x[is_back] = ik->x[is_back] + (ik->x[!is_back] <= bwt->primary && ik->x[!is_back] + ik->x[2] - 1 >= bwt->primary);
ok[2].x[is_back] = ok[3].x[is_back] + ok[3].x[2];
ok[1].x[is_back] = ok[2].x[is_back] + ok[2].x[2];
ok[0].x[is_back] = ok[1].x[is_back] + ok[1].x[2];
// oc1 = oc2 = 0;
// for (i = 3; i > c2; --i)
// {
// int2 += tl[i] - tk[i];
// oc1 += tk[i];
// oc2 += tl[i];
// }
// cout << "bwt-2 interval-2: " << int2 << ' ' << oc1 << ' ' << oc2 << endl;
}
// 每次扩展两步
bwtintv_t bwt_search2(bwt_t *bwt, const string &q)
{
bwtintv_t ik, ok[4];
int i, c1, c2, x = 0;
bwt_set_intv(bwt, bval(q[x]), ik);
ik.info = x + 1;
//cout << "bwt-2: " << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
for (i = x + 1; i + 1 < (int)q.size(); i += 2)
{
if (bval(q[i]) < 4 && bval(q[i + 1]) < 4)
{
c1 = cbval(q[i]);
c2 = cbval(q[i + 1]);
// double tm_t = realtime();
//cout << BASE[c2] << BASE[c1] << endl;
bwt_extend2(bwt, &ik, ok, 0, c1, c2);
// t7 += realtime() - tm_t;
ik = ok[c2];
ik.info = i + 1;
//cout << "bwt-2: " << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
}
else
{
break;
}
}
if (i < (int)q.size() && bval(q[i]) < 4)
{ // 最后一次扩展
c1 = cbval(q[i]);
// double tm_t = realtime();
bwt_extend(bwt, &ik, ok, 0);
// t10 += realtime() - tm_t;
ik = ok[c1];
ik.info = i + 1;
//cout << "bwt-2: " << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
}
// cout << ik.x[0] << '\t' << ik.x[1] << '\t' << ik.x[2] << endl;
return ik;
}