msw添加aln时,尝试了新的高效率的方式,结果还是差一些,代码保留,等会儿clean一下

This commit is contained in:
zzh 2026-01-17 22:54:03 +08:00
parent e335e79543
commit 3dfff494f7
4 changed files with 118 additions and 25 deletions

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@ -2,6 +2,7 @@ CC= gcc
CFLAGS= -g -Wall -Wno-unused-function -mavx2 -mavx512bw -O3
WRAP_MALLOC=-DUSE_MALLOC_WRAPPERS
SAM_EXACT= -DSAM_EXACT
SHOW_PERF= -DSHOW_PERF
SHOW_DATA_PERF= -DSHOW_DATA_PERF
FILTER_FULL_MATCH= #-DFILTER_FULL_MATCH

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@ -482,15 +482,15 @@ int mem_sort_dedup_patch(const mem_opt_t *opt, const bntseq_t *bns, const uint8_
int m, i, j;
if (n <= 1) return n;
ks_introsort(mem_ars2, n, a); // sort by the END position, not START!
for (i = 0; i < n; ++i) a[i].n_comp = 1;
for (i = 0; i < n; ++i) a[i].n_comp = 1; // 设置包含的chain只有1个
for (i = 1; i < n; ++i) {
mem_alnreg_t *p = &a[i];
if (p->rid != a[i-1].rid || p->rb >= a[i-1].re + opt->max_chain_gap) continue; // then no need to go into the loop below
for (j = i - 1; j >= 0 && p->rid == a[j].rid && p->rb < a[j].re + opt->max_chain_gap; --j) {
mem_alnreg_t *q = &a[j];
int64_t or, oq, mr, mq;
int score, w;
if (q->qe == q->qb) continue; // a[j] has been excluded
mem_alnreg_t *q = &a[j]; // 遍历i之前的所有aln
int64_t or, oq, mr, mq; // ref overlap, query overlap, min ref len, min query len
int score, w;
if (q->qe == q->qb) continue; // a[j] has been excluded
or = q->re - p->rb; // overlap length on the reference
oq = q->qb < p->qb? q->qe - p->qb : p->qe - q->qb; // overlap length on the query
mr = q->re - q->rb < p->re - p->rb? q->re - q->rb : p->re - p->rb; // min ref len in alignment

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@ -384,14 +384,101 @@ static int check_add_align(const mem_opt_t* opt, kswr_avx_t aln, int is_rev, int
// is_larger, a->rb, a->re, ma->a[0].rb, ma->a[0].re, b.rb, b.re);
kv_push(mem_alnreg_t, *ma, b); // make room for a new element
// move b s.t. ma is sorted
#if 1
#if 0
for (i = 0; i < ma->n - 1; ++i) // find the insertion point
if (ma->a[i].score < b.score)
break;
tmp = i;
for (i = ma->n - 1; i > tmp; --i) ma->a[i] = ma->a[i - 1];
ma->a[i] = b;
res = 1;
ma->n = mem_sort_dedup_patch(opt, 0, 0, 0, ma->n, ma->a);
#else
// 改一下上边这个低效的排序合并
#if 0
for (i = 0; i < ma->n - 1; ++i) // find the insertion point
if (ma->a[i].score < b.score)
break;
tmp = i;
for (i = ma->n - 1; i > tmp; --i) ma->a[i] = ma->a[i - 1];
ma->a[i] = b;
i = 0;
mem_alnreg_t* p = &b;
int need_merge = 0;
while (i < ma->n) {
if (i == tmp) {
++i;
continue;
}
mem_alnreg_t* q = &ma->a[i];
if (p->rid == q->rid && (p->rb < q->re + opt->max_chain_gap || q->rb < p->re + opt->max_chain_gap)) {
need_merge = 1;
break;
}
++i;
}
if (need_merge) {
ma->n = mem_sort_dedup_patch(opt, 0, 0, 0, ma->n, ma->a);
}
#else
mem_alnreg_t* p = &ma->a[ma->n - 1];
int merged = 0; // 是否合并的flag
int unsort_idx = ma->n - 1; // 新加入的aln还没被排序
for (i = 0; i < ma->n - 1; ++i) {
mem_alnreg_t* q = &ma->a[i];
mem_alnreg_t* pq = &ma->a[i]; // 待合并
if (p->rid == q->rid && (p->rb < q->re + opt->max_chain_gap || q->rb < p->re + opt->max_chain_gap)) {
merged = 1; // 有覆盖或交叉,需要合并
unsort_idx = i;
if (p->re < q->re) { // p在前交换一下需要q在前p在后
mem_alnreg_t* tmpp = p; p = q; q = tmpp;
}
int64_t or, oq, mr, mq; // ref overlap, query overlap, min ref len, min query len
int score, w;
or = q->re - p->rb; // overlap length on the reference
oq = q->qb < p->qb ? q->qe - p->qb : p->qe - q->qb; // overlap length on the query
mr = q->re - q->rb < p->re - p->rb ? q->re - q->rb : p->re - p->rb; // min ref len in alignment
mq = q->qe - q->qb < p->qe - p->qb ? q->qe - q->qb : p->qe - p->qb; // min qry len in alignment
if (or > opt->mask_level_redun * mr && oq > opt->mask_level_redun * mq) { // one of the hits is redundant
if (p->score < q->score) {
if (pq != q)
*pq = *q;
} else {
if (pq != p)
*pq = *p;
}
} else if (q->rb < p->rb && (score = mem_patch_reg(opt, 0, 0, 0, q, p, &w)) > 0) { // then merge q into p
pq->n_comp += q->n_comp + 1;
pq->seedcov = p->seedcov > q->seedcov ? p->seedcov : q->seedcov;
pq->sub = p->sub > q->sub ? p->sub : q->sub;
pq->csub = p->csub > q->csub ? p->csub : q->csub;
pq->qb = q->qb, pq->rb = q->rb;
pq->truesc = pq->score = score;
pq->w = w;
}
}
}
// 排序
if (merged) {
ma->n -= 1; // 因为合并了(覆盖或者交叉合并等)
b = ma->a[unsort_idx];
for (i = unsort_idx; i < ma->n - 1; ++i) {
ma->a[i] = ma->a[i + 1];
}
}
for (i = 0; i < ma->n - 1; ++i) // find the insertion point
if (ma->a[i].score < b.score)
break;
tmp = i;
for (i = ma->n - 1; i > tmp; --i) ma->a[i] = ma->a[i - 1];
ma->a[i] = b;
#endif
#endif
#endif
res = 1;
}
return res;
}
@ -581,7 +668,7 @@ static void workder_gen_sam(void* data, int idx, int tid) {
mem_alnreg_v* a = &w->regs[id];
seq_sam_t* ss = &w->sams[id];
#if 1
#if 0
int cmp = strcmp("ERR194147.1629456", s[0].name) == 0;
// int cmp = (id + w->n_processed) == 202924;
if (cmp == 1) {
@ -592,7 +679,7 @@ static void workder_gen_sam(void* data, int idx, int tid) {
#endif
int n[2] = {0};
// , nn[2] = {0};
int nn[2] = {0};
//
_clear_vec(bb[0]);
_clear_vec(bb[1]);
@ -609,11 +696,12 @@ static void workder_gen_sam(void* data, int idx, int tid) {
// 这里应该先给task排序因为u8和i16是分开排序的需要合在一起
for (k = 0; k < s[si].msw.n; ++k) {
msw_task_t* t = s[si].msw.a[k];
// mem_alnreg_t* b = &a[i].a[t->aj];
//mem_alnreg_t* b = &a[i].a[t->aj];
mem_alnreg_t* b = &bb[i].a[k];
mem_alnreg_v* ma = &a[si];
uint8_t skip = 0;
if (n[si]) { // 添加了新的aln需要检测skip
//for (j = origin_n; j < ma->n; ++j){
for (j = 0; j < ma->n; ++j) { // check which orinentation has been found
int64_t dist;
int r;
@ -622,11 +710,10 @@ static void workder_gen_sam(void* data, int idx, int tid) {
skip |= 1 << r;
}
}
// if (skip == 15)
if ((t->skip | skip) == 15)
continue;
// if ((t->skip | skip) != 15) { // 检查新添加的aln是不是把当前的任务skip掉了
#if 1
// 检查新添加的aln是不是把当前的任务skip掉了
#if 0
kswr_avx_t aln = t->aln; // fprintf(gf[0], "id-%ld score-%d te-%d qe-%d score2-%d te2-%d tb-%d qb-%d\n", s[si].id +
// w->n_processed, aln.score, aln.te, aln.qe, aln.score2, aln.te2, aln.tb, aln.qb);
if (cmp) {
@ -634,16 +721,16 @@ static void workder_gen_sam(void* data, int idx, int tid) {
aln.qe, aln.score2, aln.te2, aln.tb, aln.qb); fflush(stderr);
}
#endif
// nn[si] += 1;
nn[si] += 1;
n[si] += check_add_align(opt, t->aln, t->is_rev, bns->l_pac, b, s[si].l_seq, (uint8_t*)s[si].seq, ma, t->rb);
//}
}
}
// 处理完2个pair read之后再排序因为上面操作有插入排序后之前记录的索引就无效了所以上面不能排序要两个pair read处理完之后再排序
#if 0
#if 1
for (i = 0; i < 2; ++i) {
int tmp;
if (nn[i] > 0) {
#if 0
int origin_n = a[i].n;
int start_n = a[i].n - n[i];
for (j = 0; j < n[i]; ++j) { // 在这里排序
@ -657,15 +744,15 @@ static void workder_gen_sam(void* data, int idx, int tid) {
for (k = start_n; k > tmp; --k) a[i].a[k] = a[i].a[k - 1];
a[i].a[k] = b;
// 每添加一个aln都要sort-dedup一次
#if 1
#if 0
start_n = mem_sort_dedup_patch(opt, 0, 0, 0, start_n + 1, a[i].a);
a[i].n = start_n;
#else
start_n += 1;
#endif
}
// a[i].n = mem_sort_dedup_patch(opt, 0, 0, 0, a[i].n, a[i].a);
#endif
a[i].n = mem_sort_dedup_patch(opt, 0, 0, 0, a[i].n, a[i].a);
}
}
#endif
@ -674,6 +761,8 @@ static void workder_gen_sam(void* data, int idx, int tid) {
// 这里需要传入全局id
generate_sam(opt, bns, pac, pes, (w->n_processed + id) >> 1, s, a, ss, w->n_processed, tid);
}
_destory_clear_vec(bb[0]);
_destory_clear_vec(bb[1]);
}
// 划分matesw任务

17
run.sh
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@ -1,11 +1,14 @@
thread=64
thread=1
make clean; make -j 32
n1=~/data/dataset/D2/n1.fq.gz
n2=~/data/dataset/D2/n2.fq.gz
#n1=~/data/dataset/D2/d1.fq
#n2=~/data/dataset/D2/d2.fq
#n1=~/data/dataset/D2/n1.fq.gz
#n2=~/data/dataset/D2/n2.fq.gz
n1=~/data/dataset/D2/d1.fq
n2=~/data/dataset/D2/d2.fq
#n1=~/data/SRR25735656_1.fastq.gz
#n2=~/data/SRR25735656_2.fastq.gz
#n1=/file-data/zzh/dataset/D1/45mr1.fq.gz
#n2=/file-data/zzh/dataset/D1/45mr2.fq.gz
@ -14,8 +17,8 @@ reference=~/data/reference/fmt/human_g1k_v37_decoy.fasta
#out=/dev/null
#out=./oldsam-D2-out.sam
out=./D2-1.sam
#out=./d.sam
#out=./D2-1.sam
out=./d.sam
prog=./fastalign
#prog=/home/zzh/fastbwa